## Find algebraically in RxR using substituting method the S.S. of the two equations: X + y = 4 , 2 x – y = 5

Question

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## Answers ( )

Answer:x=3 y=1

Step-by-step explanation:x+y=4

y=-x+4

plug in the y

2x-(-x+4)=5

2x+x-4=5

3x=9

x=3

plug in x=3 into first equation to find y

y=-(3)+4

y=-3+4

y=1

Answer:Step-by-step explanation:x + y = 4 equation 1

2x – y = 5 equation 2

using substitution method,

x= 4 – y equation 3

substitute equation 3 into equation 2

2(4-y) -y = 5

8 – 2y – y = 5

8 – 3y = 5

-3y = 5 – 8

-3y = -3

divide through by -3

-3y/-3 = -3/-3

y = 1

substitue the value of y into equation 1

x + y = 4

x + 1 = 4

x = 4 – 1

x = 3

Hence, x = 3 and y = 1