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posted Jul 27 '14 at 23:06

Tony%20Bielecki's gravatar image

Tony Bielecki
131

Perhaps it is not chloroform. If you see a triplet with 1:2:1 intensities, that would suggest there is a CH2 group, which yields negative amplitude in DEPT 135. If the intensities are 1:1:1, that would be deutero-chloroform. Ideally it should not appear at all (no H, therefore no H-C transfer). If it does appear, it may be because the recycle delay is too short (first scan gives larger signal which defeats the phase cycling). Try a longer recycle delay, or use some dummy scans, and it should disappear.
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posted Jul 27 '14 at 23:10

Tony%20Bielecki's gravatar image

Tony Bielecki
131

Perhaps it is not chloroform. If you see a triplet with 1:2:1 intensities, that would suggest there is a CH2 group, which yields negative amplitude in DEPT 135.

If the intensities are 1:1:1, that would be deutero-chloroform. Ideally it should not appear at all (no H, therefore no H-C transfer). If it does appear, it may be because the recycle delay is too short (first scan gives larger signal which defeats the phase cycling). Try a longer recycle delay, or use some dummy scans, and it should disappear.

Note added soon after posting: I see that Anne Baudouin responded similarly while I was typing.

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posted Jul 27 '14 at 23:11

Tony%20Bielecki's gravatar image

Tony Bielecki
131

Perhaps it is not chloroform. If you see a triplet with 1:2:1 intensities, that would suggest there is a CH2 group, which yields negative amplitude in DEPT 135.

If the intensities are 1:1:1, that would be deutero-chloroform. Ideally it should not appear at all (no H, therefore no H-C transfer). If it does appear, it may be because the recycle delay is too short (first scan gives larger signal which defeats the phase cycling). Try a longer recycle delay, or use some dummy scans, and it should disappear.

Note added soon after posting: posting: I see that Anne Baudouin responded similarly while I was typing.

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